# How many Oxygen molecules are in a CDS protocol?

**by Dr.h.c. Andreas Ludwig Kalcker**

We know that CDS, or Chlorine Dioxide Solution, liberates oxygen in the bloodstream, but how much oxygen is actually released? Is it truly significant for our health and well-being? Although this inquiry is primarily a mathematical calculation, exploring these figures might aid in understanding the remarkable healing phenomena we are observing with the use of CDS. The impact of oxygen liberation on various bodily functions and healing processes can provide valuable insights into its effectiveness and potential benefits. This exploration could lead to a deeper comprehension of the underlying mechanisms at play when using CDS in therapeutic applications.

## How many oxygen molecules are in a CDS protocol C?

**Definition of weight percent**

Weight percent means that the weight of chlorine dioxide (ClO₂) is expressed relative to the **total weight of the solution**.

A concentration of 0.3% means that 0.3% of the total solution’s weight is ClO₂.

**Calculate the mass of ClO₂ in 10 ml 0.3% solution**

Suppose you have **1 liter of solution**, and the **density of the solution** is roughly the same as water (1 g/ml), so **1 liter ≈ 1000 grams**:

- Total weight of the solution = 1000 g
- Concentration = 0.003 (0.3%) or (3000ppm)

To calculate the weight of ClO₂:

Weight of ClO₂=0.003×1000g=3g

So, in **1 liter** of this **0.3% solution**, there are **3 grams of ClO₂**.

If the total volume of the solution changes (e.g., 10 ml etc.), you would adjust the total weight accordingly and use the same formula.

- For 10 ml of solution (≈ 10 g):

**Weight of ClO₂=0.003×10g=30mg**

**Note: Solution density**

If the density of the solution differs from that of water, you will need to adjust the total weight accordingly. In most cases, the density of water (1 g/ml) is used as a reasonable approximation unless the difference is significant.

**Convert mass to grams**

Convert 30 mg to grams:

**30 mg=30g / 1000=0.030 g**

**Calculate moles of ClO**_{2}

_{2}

The molar mass of ClO₂:

- Chlorine (Cl) = 35.453 g/mol
- Oxygen (O) = 16.00 g/mol
- Molar mass of ClO₂ =
**35.453 g/mol + 2×16.00 g/mol = 67.453 g/mol**

**Mole of ClO₂ in 10ml =0.030 g /67.453 g/mol≈0.000444 mol**

**Determine the number of oxygen molecules**

Each molecule of ClO₂ contains one oxygen O_{2} molecule, so:

**Mol of O _{2} in 10 ml= 0.000444 mol**

Now, using Avogadro's number

**6.022 x 10 ^{23} molecules/mol**

to find the number of oxygen molecules:

Number of O_{2} molecules=0.000444 mol×6.022×10^{23} molecules/mol

this gives: **≈2.678×10 ^{20} molecules**

**Average number of red blood cells in the body**

The number of **red blood cells (RBCs)** in blood can vary, but on average, a healthy adult has about

**4.5 to 5.5 million red blood cells per microliter (µl)** of blood.

To calculate the total number of red blood cells in **5 liters** of blood (everage healthy adult blood volume), follow these steps:

**Convert liters to microliters:**

There are **1,000,000 microliters (µl)** in 1 liter, so in 5 liters:

5 liters=5,000,000µl

**Calculate the total number of red blood cells:**

Using an average of **5 million RBCs per µl**:

Total RBCs=5,000,000µl×5,000,000RBCs/µl

Total RBCs=25×10^{12}RBCs

So, in **5 liters of blood**, there are approximately **25 trillion 25 x 10 ^{12} red blood cells**.

**Calculate the number of oxygen molecules per red blood cell**

Let's calculate the number of oxygen molecules per red blood cell.

**Given:**

**Total number of oxygen molecules**: 2.678×10^{20}O₂ molecules.**Total number of red blood cells**: From the previous calculation, about 25×10^{12}RBCs (25 trillion red blood cells).

To find how many oxygen molecules we have for each red blood cell, divide the total number of oxygen molecules by the total number of red blood cells:

Oxygen molecules per RBC= 2.678 x 10^{20} O_{2} molecules / 25 x10^{12} RBCs= 10,712,000 O_{2} molecules / RBC

**Result:**

For each red blood cell are approximately **10.7×10 ^{6} oxygen molecules** (about 10.7 million oxygen molecules) available .