How many Oxygen molecules are in a CDS protocol?

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Revision as of 10:29, 6 September 2024 by Andreas (talk | contribs)

by Dr.h.c. Andreas Ludwig Kalcker


How many Oxygen molecules are in a CDS protocol C ?

go through the calculations step-by-step again to ensure accuracy.

1. Calculate the Mass of ClO₂ in 10 mL

Given that 3000 ppm means 3000 mg of ClO₂ in 1 L (1000 mL):

Mass of ClO₂ in 10 mL=3000 mg/1000 mL×10 mL=30 mg

2. Convert Mass to Grams

Convert 30 mg to grams:

30 mg=30/1000 g=0.030 g

3. Calculate Moles of ClO₂

The molar mass of ClO₂:

  • Chlorine (Cl) = 35.453 g/mol
  • Oxygen (O) = 16.00 g/mol
  • Molar mass of ClO₂ = 35.453+2×16.00=67.453 g/mol

Now, calculate the moles of ClO₂: Moles of ClO₂=0.030 g /67.453 g/mol≈0.000444 mol

4. Determine the Number of Oxygen Molecules

Each molecule of ClO₂ contains two oxygen atoms, so:

Moles of O=2×0.000444 mol=0.000888 mol

Now, using Avogadro's number ($6.022 \times 10^{23} , \text{molecules/mol}$) to find the number of oxygen molecules:

Number of O molecules=0.000888 mol×6.022×1023 molecules/mol

this gives: ≈5.34×1020 molecules

5. Average Number of Red Blood Cells in the Body

Assuming an average human body has about  red blood cells.

Oxygen molecules per red blood cell = 5.34×1020 molecules/ 5×1012 RBCs ≈5.34×1020 molecules

6. Calculate the Number of Oxygen Molecules per Red Blood Cell

Now divide the total number of oxygen molecules by the number of red blood cells:

Calculating this gives: =106.800 molecules/RBC


Author's note: I want to apologize for my initial calculations due to a comma mistake, which I stated at some conference.