How many Oxygen molecules are in a CDS protocol?

by Dr.h.c. Andreas Ludwig Kalcker

We know that CDS, or Chlorine Dioxide Solution, liberates oxygen in the bloodstream, but how much oxygen is actually released? Is it truly significant for our health and well-being? Although this inquiry is primarily a mathematical calculation, exploring these figures might aid in understanding the remarkable healing phenomena we are observing with the use of CDS. The impact of oxygen liberation on various bodily functions and healing processes can provide valuable insights into its effectiveness and potential benefits. This exploration could lead to a deeper comprehension of the underlying mechanisms at play when using CDS in therapeutic applications.

How many Oxygen molecules are in a CDS protocol C ?

1. Definition of Weight Percent

Weight percent means that the weight of chlorine dioxide (ClO₂) is expressed relative to the total weight of the solution.

A concentration of 0.3% means that 0.3% of the total solution’s weight is ClO₂.

2. Calculate the Mass of ClO₂ in 10 mL 0.3% solution

Suppose you have 1 liter of solution, and the density of the solution is roughly the same as water (1 g/mL), so 1 liter ≈ 1000 grams:

• Total weight of the solution = 1000 g
• Concentration = 0.003 (0.3%)

To calculate the weight of ClO₂:

Weight of ClO₂=0.003×1000g=3g

So, in 1 liter of this 0.3% solution, there are 3 grams of ClO₂.

If the total volume of the solution changes (e.g., 10 mL etc.), you would adjust the total weight accordingly and use the same formula.

• For 10 mL of solution (≈ 10 g):

Weight of ClO₂=0.003×10g=30mg

Note: Solution Density

If the density of the solution differs from that of water, you will need to adjust the total weight accordingly. In most cases, the density of water (1 g/mL) is used as a reasonable approximation unless the difference is significant.

3. Convert Mass to Grams

Convert 30 mg to grams:

30 mg=30g/1000=0.030 g

4. Calculate Moles of ClO₂

The molar mass of ClO₂:

• Chlorine (Cl) = 35.453 g/mol
• Oxygen (O) = 16.00 g/mol
• Molar mass of ClO₂ = 35.453 g/mol+2×16.00 g/mol=67.453 g/mol

Now, calculate the moles of ClO₂:

Moles of ClO₂=0.030 g /67.453 g/mol≈0.000444 mol

5. Determine the Number of Oxygen Molecules

Each molecule of ClO₂ contains one oxygen Omolecule, so:

Moles of O₂=0.000444 mol

Now, using Avogadro's number

($6.022 \times 10^{23} , \text{molecules/mol}$)

to find the number of oxygen molecules:

Number of O₂ molecules=0.000444 mol×6.022×1023 molecules/mol

this gives: ≈2,678×1020 molecules

6. Average Number of Red Blood Cells in the Body

The number of red blood cells (RBCs) in blood can vary, but on average, a healthy adult has about 4.5 to 5.5 million red blood cells per microliter (µL) of blood.

To calculate the total number of red blood cells in 5 liters of blood, follow these steps:

Convert liters to microliters:

There are 1,000,000 microliters (µL) in 1 liter, so in 5 liters:

5liters=5,000,000µL

Calculate the total number of red blood cells:

Using an average of 5 million RBCs per µL:

Total RBCs=5,000,000µL×5,000,000RBCs/µL Total RBCs=25×10¹²RBCs

So, in 5 liters of blood, there are approximately 25 trillion red blood cells.

7. Calculate the Number of Oxygen Molecules per Red Blood Cell

Let's calculate the number of oxygen molecules per red blood cell.

Given:

• Total number of oxygen molecules: 2.678×10²⁰ O₂ molecules.
• Total number of red blood cells: From the previous calculation, about 25×10¹² RBCs (25 trillion red blood cells).

Calculate oxygen molecules per red blood cell

To find how many oxygen molecules each red blood cell carries, divide the total number of oxygen molecules by the total number of red blood cells:

Oxygen molecules per RBC= 2,678∗10²⁰ / 25∗10¹² = 10 712 000

Result:

Each red blood cell carries approximately 10.7×10⁶ oxygen molecules (about 10.7 million oxygen molecules).